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  • Euler's Totient
    20 pts · 11020 Solves · 15 Solutions
    RSA relies on the difficulty of the factorisation of the modulus N. If the prime factors can be deduced, then we can calculate the Euler totient of N and thus decrypt the ciphertext.

    Given $N = p \cdot q$ and two primes:

    p = 857504083339712752489993810777
    q = 1029224947942998075080348647219


    What is Euler's totient $\phi(N)$?

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